Lab 2: Aluminum Foil Lab

The aluminum foil lab discuses an experiment to determine the thickness (height) of a piece of Aluminum foil given its density. The purpose of performing this experiment is to use the density formula to figure out the thickness of an aluminum foil in millimeters. In this lab we were given a scale and a piece of aluminum foil. To start with our procedure, we first measured the length and the width of the foil. Next we weighed the piece of aluminum foil on the scale. Then we rearranged the density formula, so we would be solving for volume instead (v=dm). After that we plugged the corresponding values of length,width, mass, and density into the variables. We labeled x thickness during this so we could solve for the variable. Finally we converted the volume side into LxWxH and solved for Height, (X). However we then got an answer in cm, so we had to covert the answer by multiplying by 10, (10mm to one 1 cm). This led to our final answer. The data in this experiment was just a bunch of calculations. To start off, the density of the foil was 2.70g/cm^3 and the mass of the foil was .4g. The length and width of the foil was both 10.2cm and we were trying to solve for the height (X). We then set up the density formula in terms of volume and solved for X,we achieved a value of .001 cm. However we needed to convert this value into millimeter, so therefore we multiplied that value by 10 and got the final answer of .01mm. So therefore we got the thickness of the aluminum foil to be .01 mm. In conclusion, we have seemed to fulfilled the purpose of this lab, which was solving for the thickness. One thing that was surprising about this lab was how they didn't give the procedure and we had to create one on our own. One thing that was challenging about this lab was to round the final answer to the correct significant figure. All in all the lab went pretty well and we passed the objective.
(Picture of the Materials of the Lab)

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